Question

How many grams are in 2.3×10^-4 moles of calcium phosphate, Ca3 (PO3)2

Answer 1

Answer : The mass of calcium phosphate is, 0.0713 grams

Explanation : Given,

Moles of calcium phosphate, $Ca_3(PO_3)_2$ = $2.3\times 10^{-4}mole$

Molar mass of calcium phosphate, $Ca_3(PO_3)_2$ = 310.18 g/mole

Formula used :

$\text{Moles of }Ca_3(PO_3)_2=\frac{\text{Mass of }Ca_3(PO_3)_2}{\text{Molar mass of }Ca_3(PO_3)_2}$

Now put all the given values in this formula, we get the mass of calcium phosphate.

$2.3\times 10^{-4}mole=\frac{\text{Mass of }Ca_3(PO_3)_2}{310.18g/mole}$

$\text{Mass of }Ca_3(PO_3)_2=0.0713g$

Therefore, the mass of calcium phosphate is, 0.0713 grams

Answer 2

We have that for the Question "How many grams are in 2.3×10^-4 moles of calcium phosphate, Ca3 (PO3)2" it can be said that the grams of 2.3×10^-4 moles of calcium phosphate is

m=713*10^{-4}grams

From the question we are told

How many grams are in 2.3×10^-4 moles of calcium phosphate, Ca3 (PO3)2

Generally the equation for the calcium phosphate  is mathematically given as

Ca3 (PO3)2

Therefore

Ca3 (PO3)2 has a molar mass of

310 g/mol.

Hence

2.3×10^-4 moles of calcium phosphate will have

m=2.3*10^{-4} * 310

m=713*10^{-4}grams

Therefore

The grams of 2.3×10^-4 moles of calcium phosphate is

m=713*10^{-4}grams

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