Question

Please help me with this. I need to solve for x.
4ln(7x+3)+12=40

Answer 1

Answer:

$x=\frac{e^7-3}{7}$

Step-by-step explanation:

4* ln(7x+3) + 12 = 40

4* ln(7x+3) + 12 - 12 = 40 - 12

4* ln(7x+3) = 28

ln(7x+3) = 28/4

ln(7x+3) = 7

e^7 = (7x + 3)

e^7 - 3 = 7x

$x=\frac{e^7-3}{7}$