Question

A 40kg cart gains a KE of 200J. How fast does it go?

Answer 1

Answer:

3.16 m/s

Explanation:

Use the formula

$k = \frac{m {v}^{2} }{2} \\ v = \sqrt{ \frac{2k}{m} } \\ v = \sqrt{ \frac{2(200)}{40} } \\ v = 3.16 \frac{m}{s}$