Question

Use the discriminant of the following quadratic equation to describe its solutions. x2 - 16x + 64 = 0

Answer 1

$\begin{array}{lccllll} 1x^2 &- 16x &+ 64& = 0\\ \uparrow &\uparrow &\uparrow \\ a&b&c \end{array}\qquad discriminant\to b^2-4\cdot a\cdot c$

if the discriminant is
negative <-- two complex solutions
positive <-- two real solutions
0          <-- one solution