Question

Given the formula, find the first five terms and the 10th term of each
sequence.
a n = 8 – 5n
My attempt:
a1 = 8(5)5 =a1 =5
a2=8(5)6-5=10
a3=8(5)7-5=15
a4=8(5)8-5=20
a5=8(5)9-5=25
a10=8(5)10-5=a1050?

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's calculate the Given terms ~

$\textbf{1st Term :}$

$\qquad \sf  \dashrightarrow \:a_1 = 8 - 5(1)$

$\qquad \sf  \dashrightarrow \:a_1 = 8 - 5$

$\qquad \sf  \dashrightarrow \:a_1 = 3$

$\textbf{2nd Term :}$

$\qquad \sf  \dashrightarrow \:a_2 = 8 - 5(2)$

$\qquad \sf  \dashrightarrow \:a_2 = 8 - 10$

$\qquad \sf  \dashrightarrow \:a_2 = - 2$

$\textbf{3rd Term :}$

$\qquad \sf  \dashrightarrow \:a_3 = 8 - 5(3)$

$\qquad \sf  \dashrightarrow \:a_3 = 8 - 15$

$\qquad \sf  \dashrightarrow \:a_3 = - 7$

$\textbf{4th Term : }$

$\qquad \sf  \dashrightarrow \:a_4 = 8 - 5(4)$

$\qquad \sf  \dashrightarrow \:a_4 = 8 -20$

$\qquad \sf  \dashrightarrow \:a_4 = - 12$

$\textbf{5th Term :}$

$\qquad \sf  \dashrightarrow \:a_5 = 8 - 5(5)$

$\qquad \sf  \dashrightarrow \:a_5 = 8 - 25$

$\qquad \sf  \dashrightarrow \:a_5 = -17$

$\textbf{10th Term :}$

$\qquad \sf  \dashrightarrow \:a_{10} = 8 - 5(10)$

$\qquad \sf  \dashrightarrow \:a_{10} = 8 - 50$

$\qquad \sf  \dashrightarrow \:a_{10} = - 42$

Answer 2

• a_n=8-5n

#1

• a_1=8-5(1)=8-5=3

#2

• a_2=8-5(2)=8-10=-2

#3

• a_3=8-5(3)=8-15=-7

#4

• a_4=8-5(4)=8-20=-12

#5

• a_5=8-5(5)=8-25=-17

#10

• a_10=8-5(10)=8-50=-42