Question

The velocity of a free falling ball at different time intervals on unknown planet is shown in Figure 1.24.

Answer all of the following questions based on the image

A) What is the acceleration due to gravity of the planet?

B)What is the velocity at positions A and B?

C)What happens to the magnitude of velocity with passage of time? Why?

D)What factor(s) can influence the falling object on the Earth?
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Answer 1

Answer:

a1 = (V2 - V1) / 1 s = 3.75 m/s^2

a2 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2

a3 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2

A) a = (a1 + a2 + a3) / 3 = 3.75 m/s^2

v = a (t2 - t1)

B) after    1 sec    v = 3.75 m / sec^2 * 1 sec = 3.75 m/s

    after   2 sec     v = v0 + a t = 3.75 m/s + 3.75 m/s^2 * 1 s = 7.5 m/s

C)  The velocity increases proportionaly to the time

D) One factor depends on the variation of the acceleration due to gravity because of different positions of measurement (on earth)

A much larger factor is due to air resisance of the air on the falling object