Question

Which of the x values are solutions to the inequality 4(2 – x) > –2x – 3(4x + 1)? Check all that apply.

Answer 1

Step-by-step explanation:

$4(2 - x) > - 2x - 3(4x + 1)$

$8 - 4x > - 2x - 12x - 3$

$8 - 4x > - 14x - 3$

$- 4x + 14x > - 3 - 8$

$10x > - 11$

$x = - 1.1$

Answer 2

Answer:

$x > \frac{-11}{10}$

Step-by-step explanation:

Step 1:  Distribute

$4(2 - x) > -2x - 3(4x + 1)$

$(4*2)+(4 * (-x)) > -2x + (-3 * 4x) + (-3 * 1)$

$8 - 4x > -2x - 12x - 3$

Step 2:  Combine like terms

$8 - 4x > (-2x - 12x) - 3$

$8 - 4x > -14x - 3$

Step 3:  Add 14x to both sides

$8 - 4x + 14x > -14x - 3 + 14x$

$8 + 10x > -3$

Step 4:  Subtract 8 from both sides

$10x + 8 - 8 > -3 - 8$

$10x > -11$

Step 5:  Divide both sides by 10

$\frac{10x}{10} > \frac{-11}{10}$

$x > \frac{-11}{10}$

Answer:  $x > \frac{-11}{10}$