Question

If the temperature of a 50mL sample of a gas is changed from 200K to 400K under constant pressure, what is the new volume of the gas?

Answer 1

Hello There!!

Given:-

$\text{V}_1 = 50 \text{ml }\\ \text{T}_1 = 200 \text{K} \\ \text{V}_2 = ? \\ \text{T}_2 = 400 \text{K}$

To find:-

$\text{The Value of V}_2$

Solution

$\frac{ \text{V}_1}{ \text{T}_1} = \frac{ \text{V}_2}{ \text{T}_2}$

$\frac{50}{200} =\frac{ \text{V}_2}{400} \\ \\ \fbox{cross multiplying} \\ \\ \implies 200 \times V_2 = 50 \times 400 \\ \\ \implies V_2 = \frac{50 \times 400}{200} \\ \\ \implies V_2 = \frac{50 \times \cancel{ 400} { \: \: \: }^{2} }{ \cancel{200}} \\ \\ \implies V_2 = 50 \times 2 \\ \\ \implies V_2 = 100$

$\therefore \implies V_2 = 100 \text{ml}$

Hope This Helps!!