The total surface area of the remaining solid is 48(4+root3) centimeters square.
We have given that,
Through a regular hexagonal prism whose base edge is 8 cm
Whose height is 12 cm, a hole in the shape of a right prism
Total surface area=2(area of the base)+parameter of base×Height
Height=8cm
Parameter of base=12(2)=24
area of the base=6×root3/4×4^2
We use the given value in the formula
=2×6×root3/4×4^2+24×8
=48root3+192
=48(4+root3)cm^2
Therefore the total surface area of the remaining solid is 48(4+root3)cm^2.
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