Respuesta :

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

If two similar waves are traveling in the same medium, then they have same wave velocity. so we can infer that

[tex]\qquad \tt \dashrightarrow \:v_A = v_B[/tex]

Now, as per the formula ~ we know that :

[tex]\qquad \sf \dashrightarrow \:v = \lambda \cdot f [/tex]

  • v = wave velocity

  • λ = wavelength

Now, we can write it as :

[tex]\qquad \sf \dashrightarrow \: \lambda_A \cdot f_A = \lambda _B \cdot f_B[/tex]

And it's also given that frequency of wave A is 3 times that of frequency of wave B.

So, let's add the relation to our equation ~

[tex]\qquad \sf \dashrightarrow \: \lambda_A \cdot3f_B = \lambda _B \cdot f_B[/tex]

[tex]\qquad \sf \dashrightarrow \: \lambda_A \cdot3= \lambda _B[/tex]

[tex]\qquad \sf \dashrightarrow \: λ_A = \frac{1}{3}  λ_B[/tex]

So, choice C is correct ~

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