Question

C17H19NO3 compound, what is the percent by mass of carbon

Answer 1

Answer:

71.58%

Explanation:

Find the Mr of C₁₇H₁₉NO₃ :

(12 × 17) + 19 + 14 + (16 × 3) = 285

Mr of carbon in C₁₇H₁₉NO₃ :

12 × 17 = 204

Percent by mass of carbon = $\frac{204}{285}$ × 100 = 71.58%