Answer:
x = -3 , - 15
Step-by-step explanation:
Given:
x² + 18x + 45 = 0
Solve:
[tex]x_{1,\:2}=\frac{-18\pm \sqrt{18^2-4\cdot \:1\cdot \:45}}{2\cdot \:1}[/tex]
Simplify
[tex]-18\pm \sqrt{18^2-4\cdot \:1\cdot \:45=12[/tex]
[tex]x_{1,\:2}=\frac{-18\pm \:12}{2\cdot \:1}[/tex]
Separate the solution
[tex]x_1=\frac{-18+12}{2\cdot \:1},\:x_2=\frac{-18-12}{2\cdot \:1}[/tex]
[tex]x_1=\frac{-18+12}{2\cdot \:1}=-3[/tex]
[tex]x_2=\frac{-18-12}{2\cdot \:1}=-15[/tex]
Thus, the answer are:
[tex]x=-3,\:x=-15[/tex]
Kavinsky