Answer:
sin(theta) = [tex]\frac{\sqrt{7}}{4}[/tex]
Step-by-step explanation:
cos(theta) = [tex]\frac{x}{r}[/tex]
cos(theta) = [tex]\frac{3}{4}[/tex]
so x = 3 , r = 4 , and y =?
Pythagorean Theorem: x^2 +y^2 = r^2 or a^2 +b^2 = c^2
x^2 +y^2 = r^2
(3)^2 +y^2 = (4)^2
9 + y^2 = 16
y^2 = 7
[tex]y=\sqrt{7},-\sqrt{7}[/tex]
In Quadrant 1, so its only [tex]y=\sqrt{7}[/tex].
sin(theta) = [tex]\frac{y}{r}[/tex]
sin(theta) = [tex]\frac{\sqrt{7}}{4}[/tex]
