Answer: [tex]92 \text{ yd}^2[/tex]
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Work Shown:
[tex]A = \frac{h(b_1+b_2)}{2}\\\\A = \frac{8(19+4)}{2}\\\\A = \frac{8(23)}{2}\\\\A = \frac{184}{2}\\\\A = 92\\\\[/tex]
The [tex]b_1[/tex] and [tex]b_2[/tex] are the parallel bases, while h is the height perpendicular to each base.
The units are in square yards, abbreviated as [tex]\text{yd}^2[/tex]
Think of a 1 yard by 1 yard square that has an area of [tex](1 \text{ yd})*(1 \text{ yd}) = (1)^2(\text{yd})^2 = 1 \text{ yd}^2[/tex]
The side of 9 yards is never used and put in there as a distraction.
