For the given function g(x)=xpower of 2-6x-16, the statement which is true, is the zeros are -2 and 8 because the factor of g are (x+2) and (x-8).
A quadratic function is the function in which the unknown variable is one and the highest power of the unknown variable is two.
The standard form of the quadratic function is,
[tex]f(x)=ax^2+bx+c[/tex]
Here,(a,b, c) is the real numbers and (x) is the variable.
The quadratic function given in the problem is,
[tex]g(x)=x^2-6x+16[/tex]
Factorized it with split the middle term method,
[tex]g(x)=x^2-6x-16\\g(x)=x^2-8x+2x-16\\g(x)=x(x-8)+2(x-8)\\g(x)=(x-8)(x+2)[/tex]
Equate the factors of the function, to find the zeros,
[tex]x-8=0;x=8\\x+2=0;x=-2[/tex]
Hence, for the given function g(x)=xpower of 2-6x-16, the statement which is true, is the zeros are -2 and 8 because the factor of g are (x+2) and (x-8).
Learn more about the quadratic equation here;
https://brainly.com/question/1214333
#SPJ1