Question

You place air in a sealed can at standard temperature and pressure (STP). You double its absolute temperature (K) while leaving the volume constant. What happens to the pressure?

Answer 1

The pressure triples.

Answer 2

Answer:Pressure of the air inside the sealed container will get change 2 atm when absolute temperature is doubled.

Explanation:

According to question , Volume is constant

According to Gay Lussac's Law:

$Pressure\propto Temperature$ (at constant temperature)

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

At STP, the temperature ,$T_1=273 K$

At STP, the pressure =$P_1=1 atm$

On doubling the absolute temperature the pressure changes $P_2$:

On doubling the temperature= $T_2=2\times T_1$

$P_2=\frac{1 atm\times 2\times 273 K}{273 K}=2 atm$

Pressure of the air inside the sealed container will get change 2 atm when absolute temperature is doubled.