Question

À container's filled with 28 liters of argon gas at a temperature of 353 K. If the gas is
held at 4.9 atm of pressure, how many moles of the gas are in the container?

Answer 1

Answer: 4.74 moles of gas are in the container.

Explanation:

1. Use the ideal gas law. PV = nRT. and re-arrange from moles by divided RT on both sides.

2.You should get the following equation: $n=PV/RT$

3.Insert values: $n = PV/RT = \frac{(4.9 atm)(28 L)}{(0.082 (L*atm)/(K*mol)*(353K)} = 4.74 moles.$

4.There are 4.74 moles in the container.

Good luck with chemistry!