The completely factored form of f(x) = 6x³ - 13x² - 4x + 15 is f(x) = (x + 1)(2x - 3)(3x - 5)
The expression is given as:
f(x) = 6x³ - 13x² - 4x + 15
Expand the expression
f(x) = 6x³ - 19x² + 6x² + 15x - 19x + 15
Rewrite as:
f(x) = 6x³ + 6x² + 15x- 19x² - 19x + 15
Factorize the equation
f(x) = (x + 1)(6x²- 19x + 15)
Expand (6x² - 19x + 15)
f(x) = (x + 1)(6x² - 10x - 9x + 15)
Factorize the expression
f(x) = (x + 1)(2x - 3)(3x - 5)
Hence, the completely factored form of f(x) = 6x³ - 13x² - 4x + 15 is f(x) = (x + 1)(2x - 3)(3x - 5)
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