The volume that would be necessary to decrease the pressure to 1.0 atm is mathematically given as
v2=6.4l
Question Parameter(s):
A 2.0 l container of oxygen had a pressure of 3.2 atm
Generally, the equation for the is mathematically given as
P1v1=p2v2
Therefore
v2=piv1/p2
v2=2*3.2/1
v2=6.4l
In conclusion, the volume is
v2=6.4l
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