A 2.0 l container of oxygen had a pressure of 3.2 atm. what volume would be necessary to decrease the pressure to 1.0 atm? use the formula: p1v1 = p2v2 0.625 l 0.64 l 6.4 l 64 l

Respuesta :

The volume that would be necessary to decrease the pressure to 1.0 atm is mathematically given as

v2=6.4l

What volume would be necessary to decrease the pressure to 1.0 atm?

Question Parameter(s):

A 2.0 l container of oxygen had a pressure of 3.2 atm

Generally, the equation for the   is mathematically given as

P1v1=p2v2

Therefore

v2=piv1/p2

v2=2*3.2/1

v2=6.4l

In conclusion, the  volume is

v2=6.4l

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Answer:

C

Explanation:

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