The function g(x) = x² - 10x + 16 is a quadratic function whose vertex is a minimum, and the minimum value for g(x) = x² - 10x + 16 is -9
How to determine the minimum value?
The function is given as:
g(x)=x² - 10x + 16
Differentiate the function
g'(x) = 2x - 10
Set the function 0
2x - 10 = 0
Add 10 to both sides
2x = 10
Divide by 2
x = 5
Substitute 5 for x in g(x)
g(5)=5² - 10*5 + 16
Evaluate
g(5) = -9
Hence, the minimum value for g(x)=x² - 10x + 16 is -9
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