Question

√x^2+6x+9 if x<3

Pls help cant solve it

Answer 1

Answer:

F(x) < 6

Step-by-step explanation:

$\sqrt{(x^2 + 6x +9)} = \sqrt{(x+3)(x+3)} = \sqrt{(x+3)^2\\}$

This can be simplified to (x+3) and so if x is less than 3, f(x) is less than 6