Answer:
[tex]tanA=\frac{12}{20}\\\\tanB=\frac{20}{12}[/tex]
Step-by-step explanation:
[tex]tan(theta)=\frac{Opp}{Adj}[/tex]
Unless you want to solve for A and B plug that into inverse calculator.
A = tan^-1 ( 12/20 ) = 31°
A = 31.0°
B = tan^-1 ( 20/12 ) = 59.0°
B = 59.0°
