Considering the situation described, the p-value for Amy's result is of 0.0203.
At the null hypotheses, it is tested if the mean is not greater than $50,000, that is:
[tex]H_0: \mu \leq 50000[/tex]
At the alternative hypotheses, it is tested if the mean is greater, hence:
[tex]H_1: \mu > \leq 50000[/tex]
We are testing if the mean is greater than a value, hence we have a right-tailed test. Using a right-tailed test with t = 2.06 and 200 - 1 = 199 df, the p-value is of 0.0203.
More can be learned about p-values at https://brainly.com/question/26454209
#SPJ1