Answer:
lw + [tex]\frac{1}{2}[/tex] × π × [tex](\frac{l}{2} )^{2}[/tex] ⇒ Answer D is correct
Step-by-step explanation:
First, let us find the area of the semi-circle.
Area = [tex]\frac{1}{2}[/tex] × π × r²
Given that,
diameter of the semi-circle is ⇒ l
∴ radius ⇒ l / 2
Let us find it now.
Area = [tex]\frac{1}{2}[/tex] × π × r²
Area = [tex]\frac{1}{2}[/tex] × π × [tex](\frac{l}{2} )^{2}[/tex]
Secondly, let us find the area of the rectangle.
Area = length × width
Given that,
length ⇒ l
width ⇒ w
Let us find it now.
Area = length × width
Area = l ×w
Area = lw
And now let us find the total area.
Total area = Area of the rectangle + Area of the semi - circle
Tota area = lw + [tex]\frac{1}{2}[/tex] × π × [tex](\frac{l}{2} )^{2}[/tex]
