Question

What is the equilibrium constant, K, for the following reaction, if the concentration of N2 was measured to be 0.521 M, H2 was measured to be 0.482 M, and NH3 was measured to be 3.17 M

Answer 1

The equilibrium constant is the relation between the products and the reactants of the reaction. The K, for the reaction, is 172.

What is the equilibrium constant?

The equilibrium constant (K) is the relationship in the form of a ratio that denotes the concentration of the products to the reactants in a reaction.

The balanced chemical reaction is shown as,

$\rm N_{2}(g) + 3H_{2}(g) \leftrightharpoons 2NH_{3}(g)$

Given,

Concentration of nitrogen =0.521 M

Concentration of hydrogen = 0.482 M

Concentration of ammonia = 3.17 M

The value of K is calculated  as:

$\begin{aligned} \rm K &= \rm \dfrac{[NH_{3}]^{2}}{[N_{2}][H_{2}]^3}\\\\&= \dfrac{(3.17)^{2}}{(0.521)(0.482)^{3}}\\\\&= 172\end{aligned}$

Therefore, the equilibrium constant for the reaction is 172.

Learn more about the equilibrium constant here:

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