The required measure angles B and C of are 65° and 50° and value of x = 25.
Given,
The measures of the angles in △ABC are 65°
, (3x−10)°
, (2x)°.
We have to find,
The value of x Then measures of angles B and C.
According to the question,
The sum of all internal angles of a triangle is always equal to 180°.
65° + 3x − 10°
+ 2x° = 180
5x + 55 = 180
5x = 180 - 55
5x = 125
x = [tex]\frac{125}{5}[/tex]
x = 25
The required value of x = 25.
Then, The required angle are,
3x - 10 = 3(25) - 10 = 65°
2x = 2(25) = 50°
The required angles are 65° and 50° .
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