Question

(PLSSS HELP)A bag contains 10 marbles: 5 are green, 3 are red, and 2 are blue. Ivanna chooses a marble at random, and without putting it back, chooses another one at random. What is the probability that both marbles she chooses are red?

Answer 1

Answer:

$\frac{1}{15}$

Step-by-step explanation:

Let's first find the probability that she chooses a red marble the first time.

There are 10 marbles and 3 red marbles, therefore the probability of choosing a red marble is:

$\frac{3}{10}$

The second time, there are only 9 marbles remaining as she does not put the marble back. In addition, assuming she drew a red marble, there are only 2 red marbles left. Therefore the probability she chooses a red marble the second time is:

$\frac{2}{9}$

Now, we multiply the two fractions:

$\frac{3}{10}*\frac{2}{9}=\frac{6}{90}=\frac{1}{15}$

Therefore the probability that boht marbles she chooses are red is:

$\frac{1}{15}$

Answer 2

Answer:

1/15

Step-by-step explanation:

There are 10 marbles in total, 3 are red which makes a probability of 3/10.

After Ivanna randomly selects a red marble, there are 9 total marbles left and 2 red remaining. This makes the probabilty of 2/9. And since the equation asks for the probabilty of both events to be true, multiply the equation. below is how I worked out the solutions.

3/10 * 2/9 = 1/15