If the speed of every gas molecule in the sample is doubled, then the new temperature of the gas is 80K.
Speed of any molecule of gas is measured in terms of velocity and relation between root mean square velocity and temperature will be calculated as:
V = √3RT/M
Means velocity is directly proportional to the square root of the temperature, and for this question required equation is:
V₁/V₂ = √T₁/T₂
If velocity of the molecule is gets double then equation becomes,
V₁/2V₁ = √200/T₂
T₂ = 800K
Hence resultant temperature of gas is 800K.
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