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30-01-2017
Chemistry

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Cal the molarity of solution prepared by dissolving 250 of Ca(NO3)2 to make 2.5L of solution

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Willchemistry Willchemistry

01-02-2017

Molar mass Ca(NO3)2 = 164.088 g/mol

number of moles:

250 / 164.088 => 1.523 moles

Volume = 2.5 L

Therefore:

Molarity = moles / Volume

Molarity = 1.523 / 2.5

=> 0.6092 M

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