The time required to move from the equilibrium position directly to a point a will be 0.879 sec.
The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.
The standard equation for the SHM is found as;
[tex]\rm x = asin \omega t \\\\ \rm 12.3 \times 10^{-2} = 18.0 \times 10^{-2}sin \omega t \\\\ 0.6833=sin \omega t \\\\ \omega t =sin^{-1}0.6833 \\\\ \omega t =0.7522 \\\\ t = \frac{0.7522}{0.855 } \\\\ t=0.879\ sec[/tex]
Hence the time required to move from the equilibrium position directly to a point a will be 0.879 sec.
To learn more about the period of oscillation refer to the link;
https://brainly.com/question/14394641
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