The age of the fossil which contains the Carbon-14 radioactive isotope is 11460 years
How to determine the number of half-lives
- Original amount (N₀) = 100%
- Amount remaining (N) = 25%
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = 100 / 25
2ⁿ = 4
2ⁿ = 2²
n = 2
How to determine the age
- Half-life (t½) = 5730 years
- Number of half-lives (n) = 2
- Time (t) =?
t = n × t½
t = 2 × 5730
t = 11460 years
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