Question

Find four consecutive odd integers such that if the sum of the first and fourth is multiplied by three, the result
is 12 less than four times the third.

Answer 1

Answer:

-7, -5, -3, -1

Step-by-step explanation:

Let x be the smallest of the four consecutive odd integers. Then the next three consecutive odd integers are x+2, x+4, and x+6. We have:

$3(x + x + 6) = 4(x + 4) - 12$

$3(2x + 6) = 4(x + 4) - 12$

$6x + 18 = 4x + 16 - 12$

$6x + 18 = 4x + 4$

$2x = - 14$

$x = - 7$

So the four consecutive odd integers are -7, -5, -3, and -1.