Question

When my pot of paint is half full, it weighs 5.8 kg. When my pot of paint is one quarter full, it weighs 3.1 kg.
What is the weight of the full pot?

Answer 1

The paint in the pot is an illustration of a linear equation and the weight of the full pot is 11.2 kg

How to determine the weight of the full pot?

The given parameters can be represented using the following ordered pairs:

(x,y) = {(0.5, 5.8) and (0.25, 3.1)}

The slope of the equation is calculated using:

m = (y2 - y1)/(x2 - x1)

This gives

m = (3.1 - 5.8)/(0.25 - 0.5)

Evaluate

m = 10.8

The equation is then calculated using:

y = m(x - x1) + y1

This gives

y =  10.8(x - 0.5) + 5.8

Expand

y =  10.8x + 0.4

When the pot is full, we have x = 1

So, the equation becomes:

y =  10.8 * 1 + 0.4

Evaluate

y =  11.2

Hence, the weight of the full pot is 11.2 kg

Read more about linear equations at:

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