The concentration of the hydronium ion is 0.15 M and the concentration of the hydroxide ion is 6.30 × 10 ⁻¹⁰.
pH is the negative logarithm of the hydrogen ion concentration, while pOH is the measure of the hydroxide ion concentration.
The hydronium ion concentration of the solution is calculated as:
[tex]\begin{aligned} \rm (H_3}\rm O^{+}) &= \rm antilog (-pH)\\\\&= \rm antilog (-4.8)\\\\&= 1.58489\times 10^{-5} \;\rm M\end{aligned}[/tex]
pOH is calculated as:
[tex]\begin{aligned}\rm pH + pOH &= 14\\\\&= 14 - 4.8\\\\&= 9.2 \end{aligned}[/tex]
The concentration of the hydroxide ion is calculated as:
[tex]\begin{aligned} \rm pOH &= \rm - log [OH^{-}]\\\\&= \rm -antilog (9.2)\\\\&= 6.30 \times 10^{-10}\end{aligned}[/tex]
Therefore, the hydronium ion concentration is [tex]1.58489\times 10^{-5} \;\rm M[/tex] and hydroxide is [tex]6.30 \times 10^{-10}.[/tex]
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