Which is an equation of the line that passes through the points (5,2) and (10,-3)?
A. y = x - 3
B. y = x - 8
C. y = -x + 7
D. y = -x + 12

Respuesta :

Answer:

C

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (5, 2 ) and (x₂, y₂ ) = (10, - 3 )

m = [tex]\frac{-3-2}{10-5}[/tex] = [tex]\frac{-5}{5}[/tex] = - 1 , then

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (5, 2 ), then

2 = - 5 + c ⇒ c = 2 + 5 = 7

y = - x + 7 ← equation of line

The answer is C

You get this by first finding the slope between the two points
Y2 - Y1
X2 - X1
It gives you 5/-5 which is -1
So you can narrow it down to options C and D

Now you can just substitute into both equations

2 = -(5) + 7
2 = 2

-3 = -(10) + 7
-3 = -3

Since both coordinates work in C then C is the answer
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