Answer:
(1;1) and (0;4)
Step-by-step explanation:
1) if given f(x)=3x²-6x+4 (where a=3; b=-6 and c=4), then
[tex]x_0=\frac{-b}{2a}; \ = > \ x_0=1;[/tex]
[tex]y_0=3*1-6*1+4=1;[/tex]
it means, the vertex has coordinates (1;1).
2) if according to the condition x=0, then
f(0)=0-0+4=4;
it means the Y-intercept is 4.
