Question

The current in the wires of a circuit is 120.0 milliAmps. If the
resistance of the circuit were halved (i.e., reduced to one-
half the original value) (with no change in voltage), then its
new current would be
milliAmps.

Answer 1

If the resistance of the circuit were halve and the voltage remains constant, the new current in the circuit would be 240 mA.

Current in the circuit

The current in the circuit is inversely proportional to the resistance of the circuit. This implies that the increase in the resistance of the circuit decreases the current in the circuit.

V = IR

At constant voltage;

I₁R₁ = I₂R₂

when, R₂ = 0.5R₁

I₂ = I₁R₁ /R₂

I₂ = I₁R₁ /0.5R₁

I₂ = 2I₁

I₂ = 2 x 120 mA

I₂ = 240 mA

Thus, if the resistance of the circuit were halve and the voltage remains constant, the new current in the circuit would be 240 mA.

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