prayerallen2000 prayerallen2000

28-04-2022
Chemistry

contestada

How much heat must be removed from 75.0 g of water at 90.0°C to cool it to 23.0°C?

Respuesta :

jsimpson11000 jsimpson11000

06-05-2022

Answer:

See below

Explanation:

75 g * ( 90 - 23) C * 1 cal / g-C

= 5025 cal = 21 034 .7 J

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