Respuesta :
Answer:
π 36 m^2
Step-by-step explanation:
C = 2π R = 12π m --> R = 6m
A = π R^2 = π 36 m^2
Answer:
- Area of circle = 36π m²
Step-by-step explanation:
In the question we are given that circumference of circle is 12π m . And we are asked to find the area of circle in term of π .
Solution : -
For finding area of circle we need to find the radius of circle . In the question circumference of circle is given . So we can find radius of circle using it . We know that ,
[tex] \qquad \quad \pink{\underline{\pink{\boxed{\frak{Circumference_ {(Circle) }= 2\pi r}}}}}[/tex]
Where ,
- π refers to 3.14 or 22/7
- r refers to radius of circle
But as in the question , it is given that we have to find the area in term of π. So we aren't using π as 3.14 or 22/7 .
Now, Radius :
[tex] \longrightarrow \qquad \: 12 \cancel{\pi }= 2 \cancel{\pi} r[/tex]
Step 1 : Cancelling π and we get :
[tex] \longrightarrow \qquad \:12 = 2r[/tex]
Step 2 : Dividing both sides by 2 :
[tex] \longrightarrow \qquad \: \cancel{\dfrac{12}{2} } = \dfrac{ \cancel{2}r}{ \cancel2} [/tex]
On further calculations we get :
[tex] \longrightarrow \qquad \: \boxed{ \bf{r = 6 \: m}}[/tex]
- Therefore , radius of circle is 6 m .
Finding Area :
As we have find the radius of circle above so we can find its area easily . We know that ,
[tex] \qquad \: \qquad \pink{\underline{\pink{ \boxed{{\frak{ Area_{(Circle)} = \: \pi r {}^{2} }}}}}}[/tex]
Now substituting value of radius :
[tex] \longmapsto \: \qquad \quad\pi (6) {}^{2} [/tex]
[tex] \longmapsto \: \qquad \quad \pi \times \: 6 \times 6[/tex]
[tex] \longmapsto \: \qquad \quad \pi \times 36[/tex]
We get :
[tex] \longmapsto \: \qquad \quad \blue{\underline{\blue{\boxed{\frak{ \bf{36 \pi \: m {}^{2} }}}}}}[/tex]
- Therefore, area of circle is 36π square metres .