Respuesta :

Answer:

π 36 m^2

Step-by-step explanation:

C = 2π R = 12π m --> R = 6m

A = π R^2 = π 36 m^2

Answer:

  • Area of circle = 36π

Step-by-step explanation:

In the question we are given that circumference of circle is 12π m . And we are asked to find the area of circle in term of π .

Solution : -

For finding area of circle we need to find the radius of circle . In the question circumference of circle is given . So we can find radius of circle using it . We know that ,

[tex] \qquad \quad \pink{\underline{\pink{\boxed{\frak{Circumference_ {(Circle) }= 2\pi r}}}}}[/tex]

Where ,

  • π refers to 3.14 or 22/7

  • r refers to radius of circle

But as in the question , it is given that we have to find the area in term of π. So we aren't using π as 3.14 or 22/7 .

Now, Radius :

[tex] \longrightarrow \qquad \: 12 \cancel{\pi }= 2 \cancel{\pi} r[/tex]

Step 1 : Cancelling π and we get :

[tex] \longrightarrow \qquad \:12 = 2r[/tex]

Step 2 : Dividing both sides by 2 :

[tex] \longrightarrow \qquad \: \cancel{\dfrac{12}{2} } = \dfrac{ \cancel{2}r}{ \cancel2} [/tex]

On further calculations we get :

[tex] \longrightarrow \qquad \: \boxed{ \bf{r = 6 \: m}}[/tex]

  • Therefore , radius of circle is 6 m .

Finding Area :

As we have find the radius of circle above so we can find its area easily . We know that ,

[tex] \qquad \: \qquad \pink{\underline{\pink{ \boxed{{\frak{ Area_{(Circle)} = \: \pi r {}^{2} }}}}}}[/tex]

Now substituting value of radius :

[tex] \longmapsto \: \qquad \quad\pi (6) {}^{2} [/tex]

[tex] \longmapsto \: \qquad \quad \pi \times \: 6 \times 6[/tex]

[tex] \longmapsto \: \qquad \quad \pi \times 36[/tex]

We get :

[tex] \longmapsto \: \qquad \quad \blue{\underline{\blue{\boxed{\frak{ \bf{36 \pi \: m {}^{2} }}}}}}[/tex]

  • Therefore, area of circle is 36π square metres .

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