Respuesta :

Answer:

[tex]\textsf{B)}\quad \dfrac{1}{28^2}[/tex]

[tex]\textsf{C)} \quad \dfrac{7^{-2}}{4^2}[/tex]

Step-by-step explanation:

[tex]4^{-2} \cdot 7^{-2}[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b \cdot c^b)=(ac)^b:[/tex]

[tex]\implies (4 \cdot 7)^{-2}[/tex]

[tex]\implies (28)^{-2}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:[/tex]

[tex]\implies \dfrac{1}{28^2}[/tex]

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Also,

[tex]4^{-2} \cdot 7^{-2}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{-n}=\dfrac{1}{a^n}:[/tex]

[tex]\implies \dfrac{7^{-2}}{4^2}[/tex]

[tex]\\ \rm\Rrightarrow 4^{-2}7^{-2}[/tex]

  • a^{-n}=1/a^n

[tex]\\ \rm\Rrightarrow \dfrac{1}{4^2.7^2}[/tex]

  • a^n×b^n=(ab)^n

[tex]\\ \rm\Rrightarrow \dfrac{1}{(4.7)^2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{1}{28^2}[/tex]

If we break only 4

[tex]\\ \rm\Rrightarrow \dfrac{7^{-2}}{4^2}[/tex]

Option B and C

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