Question

PLEASE HELP!!! WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER

In circle k(O), AC is a diameter, AB is a chord, and MA is tangent to the circle. Angle MAB is acute. Prove that mMAB=mACB.​

Answer 1

Let's call C the point on K(O) and segment AO.  I assume you're aware of a 'secant tangent angle theorem', where if you know the measure of arc BC you can solve for angle BAD.  Since CD is a diameter of the circle, the measure of arc CD is 180 degrees - with this you can easily find the measure of all arcs of the circle then apply the theorem