Please help me
I dont understand this

Answer:
[tex]y=-5(x+2)-1[/tex]
[tex]y=-5(x+3)+4[/tex]
Step-by-step explanation:
Two points on the line are (-3, 4) and (-2, -1)
Therefore:
[tex]\textsf{let}\:(x_1,y_1)=(-3,4)[/tex]
[tex]\textsf{let}\:(x_2,y_2)=(-2,-1)[/tex]
[tex]\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-1-4}{-2-(-3)}=-5[/tex]
Point-slope form of linear equation: [tex]y-y_1=m(x-x_1)[/tex]
Substituting point (-3, 4) in the point-slope equation:
[tex]\implies y-4=-5(x-(-3))[/tex]
[tex]\implies y=-5(x+3)+4[/tex]
Substituting point (-2, -1) in the point-slope equation:
[tex]\implies y-(-1)=-5(x-(-2))[/tex]
[tex]\implies y=-5(x+2)-1[/tex]