Question

. What is the vertical asymptote(s) for y=x-5/x^2-4x-12​

Answer 1

Answer:

4x=5y

Step-by-step explanation:

it gave the answer

Answer 2

Answer:

x = -2 and 6

Step-by-step explanation:

To find vertical asymptote, set the denominator equal to 0 and solve for x. See the guidelines below for determining VA

$y=\frac{x-5}{x^{2} -4x-12}$

$x^{2} -4x-12=0$

$x^{2} -6x+2x-12=0$

$x(x-6)+2(x-6)=0$

$(x+2)(x-6)=0$

$x=-2,6$

Hope this helps and God bless!