Answer:
8
Step-by-step explanation:
We know that
Equation
[tex] {x}^{2} + {y}^{2} + 2gx + 2fy + c = 0[/tex]
Represents the equation of Circle
where
[tex]radius = \sqrt{ {g}^{2} + {f}^{2} - c } [/tex]
On comparing the given equation with general Equation of Circle
we get
[tex]g = - 5[/tex]
[tex]f = 3[/tex]
[tex]c = - 30[/tex]
On substituting these values We get
[tex]radius = \sqrt{ { (- 5)}^{2} + {3}^{2} - ( - 30) } [/tex]
[tex]radius = \sqrt{25 + 9 + 30 } = \sqrt{64 } = 8[/tex]
[tex]radius = 8[/tex]
