Question

At what pressure will 4.80 moles of fluorine gas have a volume of 60.0 liters and a temperature of 298 K?

Answer 1

The pressure of the given mol of fluorine as an ideal gas at the given temperature and volume is 1.96atm.

Ideal Gas Law

The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.

It is expressed as;

PV = nRT

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )

Given the data in the question;

• Amount of fluorine gas n = 4.80moles

• Volume V = 60.0L

• Temperature T = 298K

• Pressure P = ?

To determine the pressure of the fluorine gas, we substitute our values into the expression above.

PV = nRT

P = nRT / V

P = ( 4.80mol × 0.08206Latm/molK × 298K ) / 60.0L

P = 117.378624Latm / 60.0L

P = 1.96atm

Therefore, the pressure of the given mol of fluorine as an ideal gas at the given temperature and volume is 1.96atm.

Learn more about Ideal Gas Law here: brainly.com/question/4147359