Question

The force acting on a body of mass 200 g is equal to 0. Determine the velocity of the body 3 seconds after the start of the observation, if at the initial moment of the observation its velocity is 5 m / s?​

Answer 1

Answer:

• 5 m/s

Explanation:

Formula (Force)

• F = ma
• But, a = v - u / t [First Equation of Motion]
• F = m (v - u / t)

We have the values of :

• F = 0
• m = 200 g = 0.2 kg
• t = 3 s
• u = 5 m/s

Substitution

• 0 = 0.2 (v - 5 / 3)
• v - 5 / 3 = 0
• v - 5 = 0
• v = 5 m/s