Question

A particle with a charge of +8nC is in a uniform electric field directed to the left. It is released from rest and moves to the left. After it as moved 3cm, its kinetic energy was found to be 5x 10^(-4) J. What work was done by electric force?

Answer 1

The work done by the electric force of the charge is equal to the change in kinetic energy, equal to 5x $10^{-4}$ J.

What is the work-energy theorem?

The work done by the body in motion is equal to the change in kinetic energy or the difference between the final and initial kinetic energy.

$W=$Δ$K.E=K.E_{f} -K.E_{i}$

Given, the kinetic energy found when the charge has moved 3 cm is  5x $10^{-4}$ J.

Therefore, work done by the electric force, $W=$  5x $10^{-4}$ J.

Learn more about the work-energy theorem.

https://brainly.com/question/10063455

#SPJ1