Question

The vertices of a right triangle are p(-3,4), q(-3,-4) and r (7,-4). Explain algebratically whether or not (2,0) is on the side of the triangle.

Answer 1

Algebraically, it was possible to show that the point (2,0) is on the side (PR) of the given triangle.

RIGHT TRIANGLE

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  In this triangle from the trigonometric ratios or the Pythagoras Theorem ($(hypotenuse)^2=(side_1)^2+(side_2)^2$), it is possible finding angles or sides.

The question gives the points for a right triangle, you can draw the triangle, see the attached image. From the figure, it is possible to see the lengths for the sides PQ=8 and QR=10.

Linear Equation

A linear function can be represented by a line. The standard form for this equation is: ax+b , for example, y=2x+7. Where:

a= the slope. If

• a> 0 , the function is increasing;
• a< 0 , the function is decreasing;

b=the constant term that represents the y-intercept.

The slope for the line PR can be calculated from the ratio between the side PQ and QR.

$a=\frac{PQ}{QR}=\frac{4-(-4)}{(-3-7)}=\frac{8}{-10} =-0.8$

From the attached figure, it is possible to see that the y-intercept is (2,0). Therefore, the given point is on the side PR, but the question asks to show this algebraically.

From the Standard form (ax+b), the equation for the line PR will be:                      y=- 0.8x+b. After that, you should replace the coordinates of the given point P (-3,4) in the equation line:  y=-0.8x+b for finding b.

4=-0.8*(-3)+b

4=2.4+b

b=4-2.4= 1.6

Then, the equation line y=-0.8x+1.6.

Now you should replace the x-coordinate for the point (2,0) in the equation  y=-0.8x+1.6.

y=-0.8*2+1.6

y=-1.6+1.6

y=0

The calculated y-coordinate is the same the y-coordinate for the point (2,0), thus the point (2,0) is on the side of the triangle.

Read more about the linear equation here:

brainly.com/question/12242745