Question

Car A can travel around a curved section of road without skidding at a maximum constant speed of 10 m/s. When car B travels around the same curve without skidding at its maximum speed, it has twice the centripetal acceleration as car A. The maximum speed at which car B can safely travel around the curve is most nearly

Answer 1

Answer:

C) 14 m/s

Explanation:

First step is to work out the centripetal acceleration of Car A. The equation for centripetal acceleration is:

a = v^2 / r

So we substitue in the value given for Car A's speed and get:

a = (10)^2 / r

a = 100 / r

We know that Car B has twice the centripetal acceleration of Car A, or 2a, therefore:

2a = 2 ( 100 / r ) = 200 / r

Now we know the centripetal acceleration of Car B! Last step: we use a = v^2 / r to find the velocity of Car B:

a = v^2 / r

200 / r = v^2 / r (r's cancel)

v^2 = 200

v = 14.1 m/s

Hope that helped! Sorry, I have no idea how to use the equation tool.