To eight significant figures, avogadro's constant is 6.0221367×1023mol−1. which of the following choices demonstrates correct rounding?

2. Pay attention to the digits afterward (right). If the digit shows the numbers 0, 1, 2, 3 or 4, then the digit to be rounded is fixed, and the digit on the right is 0

3. If the digit on the right shows the numbers 5, 6, 7, 8 or 9, then the digit to be rounded is added to one, and the digit on the right side is made all 0

for example, In rounding the nearest hundreds number, then we see the digit in the number tens (right of the digit hundreds), if it is worth 0, 1, 2, 3 or 4, then it remains, but if it shows numbers 5, 6, 7, 8 or 9, then the digit to be rounded is added one, and the right-hand side is 0

Choice of answer we add from the problem above:

6,022 × 10²³mol⁻¹

6.0 × 10²³mol⁻¹

6,02214 × 10²³mol⁻¹

For the Avogadro number of 6.0221367 × 10²³mol⁻¹

1. If we round into a 4 digit significant number, we see the digit after the number from the 4th digit of the 6.022 number (i.e. 2)

After this 4th digit we see number 1 so the rounding remains to be: 6,022

2. For Avogadro numbers on rounding to 2 digits, because the number after 0 at number 6.0 is 2 then the rounding is fixed so that it is worth 6.0

3. For Avogadro numbers in rounding to 6 digits, because the number after 3 at number 6.0221367 is 6 then rounding up so that it is worth 6.02214

So all of the answer choices are correct

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Keywords: round up, round down, the rounded digit